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Davisson and Germer Experiment Quiz

Check your knowledge about Davisson and Germer Experiment, for clarity of physics concept, you can attempt this Quiz.

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Quiz Davisson and Germer Experiment

This quiz will help you how you have learn about the concepts of the Davisson and Germer Experiment. Check your learning and concepts.

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1. Q. Diffraction satisfies the condition;

 
 
 
 

2. Q. By the Davisson and Germer Experiment electrons shows diffraction characteristics. Is it possible to use & test the neutrons and protons particles also, in this experiment to demonstrate the diffraction? In other words dual nature of neutrons and protons particles.

Option you have;

A. Yes

B. No

C. Maybe

D. 50% chance

 
 
 
 

3. Q: de-Broglie Hypothesis of Matter Waves says, all material particles in motion have wave nature also. The wave associated with moving particles of matter are called “de-Broglie waves” or “matter waves”.

If the Energy of a photon is ; E= hν

The de-Broglie wavelength of the photon would be,

 

 

 
 
 
 

4. Q. In the Davisson Germer experiment, electrons emits from the filament i.e., tungsten. Is it true?

 

A. Yes

B. No

C. Maybe

D. 50%

 
 
 
 

5. Q. The formula associated with the electrons accelerated by a potential difference V is;

Select the correct option-

A.  lambda = 12.27/V

B.  lambda = 12.47/√V

C.  lambda = 12.07/V

D.  lambda = 12.27/√V

 
 
 
 

6. Q. Diffraction is;

 
 
 
 

7. 10 Q. From the experiment observations, Davisson and Germer observed a most prominent bump. They explained it with the help of?

 
 
 
 

8. Q. The year in which Davisson and Germer Experiment was performed to detect the electron diffraction is;

 
 
 
 

9. Q. Let us consider a specific case of electron. If the electron acquires kinetic energy on being accelerated from rest through a potential difference of V volt, then KE = eV, if e is the electron charge, what would be the de- Broglie wavelength,

 

a.  lambda = h/sqrt{2meV}

b. lambda = h/sqrt{meV}

c. lambda = h/sqrt{2mKEV}

d. lambda = h/sqrt{meV}

 

 
 
 
 

10. Q. The Angle in between the incident beam and the scattered beam (enter into collector) is known as;

 
 
 
 

Question 1 of 10

 

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