Theory of Interference Quiz

Last updated on Sunday, August 16th, 2020

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Theory of interference quiz includes basic fundamental quaestions to judge and provide an angle to learn more about the topic.

Interference is a phenomena when two or more than two waves of same frequency with a constant initial phase difference meets or superimpose in a specific region the intensity of these waves distributes in a defined manner. somewhere it becomes maximum and somewhere minimum. In this quiz we will cover some basic concepts of the interference and related numericals.

1. In the Principle of Superposition, mathematical expression where we explain the minima and maxima condition for the interference, we consider mathematical assumptions; one is

a1 + a2 Cosδ = A Cos Φ

what is the second one, select right one and give the answer.

(a) a2 Sinδ = A Sin Φ

(b) a1 + a2 Sinδ = A Sin (Φ +δ)

(c) a2 SinΦ = B Sin δ

(d) a1 + a2 Cosδ = A Cos (Φ +δ)

 
 
 
 

2. A source is coherent if it satisfy the condition;

 
 
 
 

3. In this expression;

I = (a1 – a2)2 + 4 a1a2 Cos2 (δ/2);

a1 and a2 are constants, the intensity depends only on the constant phase difference value that is δ . Then intensity will be minimum if;

(a) Cos2 (δ/2)= +2

(b) Cos δ = +1

(c) Cos δ = -1

(d) Cos δ/2 = -2

 

 

 

 
 
 
 

4. For bright fringe or maximum intensity at the centre (say O), the path difference must be an even multiple of the half-wavelength (λ/2) of light used. In a two slit experiment the distance of the nth bright fringe from the point O will be;

(a) \fn_phv \large y_{n}=\frac{nD \lambda }{2d}

(b) \fn_phv \large y_{n}=\frac{nd \lambda }{2D}

(c) \fn_phv \large y_{n}=\frac{D \lambda }{2d}

(d) \fn_phv \large y_{n}=\frac{2nD }{d \lambda}

 
 
 
 

5. The relationship between path difference and phase difference is;

(a) Path difference = 2λ/π x Phase difference

(b) Path difference = 2π/λ x Phase difference

(c) Phase difference = λ/2π x Path difference

(d) Path difference = λ/2π x Phase difference

 
 
 
 

6. In this expression;

I = (a1 – a2)2 + 4 a1a2 Cos2 (δ/2);

a1 and a2 are constants, the intensity depends only on the constant phase difference value that is δ . Then intensity will be maximum if;

(a) Cos2 (δ/2)= -1

(b) Cos δ = +1

(c) Cos δ = -1

(d) Cos δ/2 = +2

 

 

 

 
 
 
 

7. The distance of the nth dark fringe from centre point O is;

(a) \fn_phv \large y_{n}= \left ( n+\frac{1}{2} \right )\frac{D \lambda}{2d}

(b) \fn_phv \large y_{n}= \left ( 2n-\frac{1}{2} \right )\frac{D \lambda}{2d}

(c) \fn_phv \large y_{n}= \left ( n-\frac{1}{2} \right )\frac{d \lambda}{2D}

(d) \fn_phv \large y_{n}= \left ( n-\frac{1}{2} \right )\frac{D \lambda}{2d}

 

 
 
 
 

8. Angular Fringe Width

angular fringe width

 

The angular fringe width is defined as the angular separation between consecutive bright or dark fringes.

Here tan θ = Fringe width / Distance

because this angle is very small so you can write;

θ=Fringe width / Distance

What will be the result for angular fringe width;

(a) \fn_phv \large \textup{Fringe width}=\frac{2\lambda}{D}

(b) \fn_phv \large \textup{Fringe width}=\frac{\lambda}{2D}

(c) \fn_phv \large \textup{Fringe width}=\frac{\lambda}{2d}

(d) \fn_phv \large \textup{Fringe width}=\frac{2\lambda}{d}

 
 
 
 

9. The resultant intensity of light at any point is

\fn_phv \large I=a_{1}^{2}+a_{2}^{2}+2a_{1}a_{2}cos\delta

The avaerage intensity is solved as;

\fn_phv \large I_{av}=\frac{\int_{0}^{2\pi }2\pi I d\delta}{\int_{0}^{\pi}d \delta}

 

 

The average intensity result is ;

(a) I1+I2

(b)  I1 – I2

(c) I1 x I2

(d) I1 / I2

 

 

 
 
 
 

10. The coherent sources whose intensity ratio is 81:1 produce interference fringes. Deduce the ratio of maximum intensity to minimum intensity in fringe system.

 
 
 
 

Question 1 of 10

READ ALSO: Michelson Interferometer Quiz

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Dr Sushil Kumar
Dr. Sushil Kumar, a physicist, an eminent researcher and a teacher for the benefit of students and fellow physicists alike. Apni Physics is an effort to create a better platform and also to help the students to be able to have content at their hands whenever they want, online. Dr. Sushil continues to upload his lectures and post articles about latest researches in physics, academic, physics education, and also lessons about daily life and how physics define every aspect of our everyday movement and life.

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